https://www.dandwiki.com/w/api.php?action=feedcontributions&user=80.187.107.225&feedformat=atomD&D Wiki - User contributions [en]2024-03-29T15:49:22ZUser contributionsMediaWiki 1.35.8https://www.dandwiki.com/w/index.php?title=UA_talk:Players_Roll_All_the_Dice&diff=456487UA talk:Players Roll All the Dice2010-02-12T21:49:15Z<p>80.187.107.225: </p>
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<div>== Why 11? ==<br />
Does anyone know why this rule adds 11 instead of, say 10? My group might implement this rule and we're curious about where 11 comes from. My only answer is Wizard's found something in there tests, but this topic of probability is beyond me.--[[User:Windandfire|windandfire]] 16:54, 30 July 2008 (MDT)<br />
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:The average roll on a d20 is 10.5. On a .5, you usually round up. Hence, 11. --[[User:Daniel Draco|Daniel Draco]] 22:26, 30 July 2008 (MDT)<br />
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::I would have thought the average on a d20 is 10. That's interesting, thanks.--[[User:Windandfire|windandfire]] 23:02, 30 July 2008 (MDT)<br />
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::Actually, it's because you have a 50% chance of rolling a natural 1 through 10, and a 50% chance of rolling a natural 11 through 20. —[[User:Sledged|Sledged]] ([[User talk:Sledged|talk]]) 09:30, 31 July 2008 (MDT)<br />
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::I'm surprised they didn't use the standard D&D convention of "always round down". --[[User:Aarnott|Aarnott]] 11:08, 31 July 2008 (MDT)<br />
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:: Isn't the math wrong on this rule? All else being equal, attacks hit 55% of the time (1d20 vs. 10 succeeds on 10-20). Defenses should therefore stop an attack 45% of the time, meaning that the number should be 12, not 11 (1d20 vs. 12 succeeds on 12-20). --[[Special:Contributions/80.187.107.225|80.187.107.225]] 21:49, 12 February 2010 (UTC)</div>80.187.107.225